DATE OF SUBMISSION : 31.05.2018
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DATE OF SUBMISSION : 03.01.2018
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DATE OF SUBMISSION : 13.11.2017
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SUBMISSION DATE :18.09.17
HW 1 SUB TOPIC : AREAS OF SIMILAR TRIANGLES
1.
ABC & DBE are two
equilateral triangles such that D is the mid point of BC . Find the ratio of
the areas of triangles ABC & BDE
2.
If the areas of two similar
triangles are equal , prove that they are congruent
3.
Sides of two similar triangles
are in the ratio 4:9 , find the ratio of
their areas
4.
Line segment XY is parallel to
side AC of ∆ABC and it divides
the triangle into two parts of equal area . Find the ratio AX/AB
HW 2 SUB TOPIC : PYTHAGORAS THEOREM
1.Sides of triangles are given below .
Determine which of them are right triangles. In case of a right triangle ,
write the length of its hypotenuse
(i) 7cm , 24cm , 25 cm
(ii) 3cm ,8cm , 6cm
(iii) 5ocm , 80cm , 100cm
(iv) 13cm , 12cm , 5cm
2. ABD is a triangle rt angled at A &
AC Ʇ BD . Show that (i) AB2 = BC . BD
(ii) AC2 = BC . DC (iii) AD2 = BD . CD
3. ABC is an isosceles triangle rt angled
at C . Prove that AB2 = 2 AC2
4. ABC is an isosceles triangle with AC =
BC . If AB2 = 2 AC2 , prove that ABC is a right triangle
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SUBMISSION DATE :16 .08.17
HW 1 SUB TOPIC : FORMING AN AP
1. Write first four terms of the AP when first term & common difference are given
(a) A = 10 , d = 10
(b) A= - 2 , d = 0
(c) A= - 1.25 , d= 0.25
2. In the following AP write the first term & common difference
(a) – 5 , - 1 , 3 , 7
(b) 1/3 , 5/3 , 9/3 ,13/3
(c) 0.6 , 1.7 , 2.8 , 3.9
3. Find whether the following form an AP? If so find the common difference & first three terms
(a) 2 ,4 , 8 , 16 …
(b) 2 , 5/2 , 3 , 7/2 …
(c) – 1.2 , - 3.2 , - 5.2 , - 7.2
(d) 0.2 , 0.22 , 0.222 , 0.2222 , …
(e) 0 , - 4 , - 8 ,- 12 …
(f) – ½ , - ½ , - ½ , …
(g) 1,3,9,27,…
(h) a , 2a , 3a , 4a , …
(i) a , a2 , a3 , a4 , …
(j) 12 , 32 , 52 , …
HW 2 SUB TOPIC : nth term of an AP – statement problems
1. How many multiples of 4 lie between 10 & 250 ?
2. For what value of n are the nth term of two AP 63 , 65 , 67 , .. 3 , 10 , 17 , .. equal ?
3. Determine the AP whose third term is 16 & the seventh term exceeds the eighth term by 12 ?
4. Subha Rao started work in 1995 at an annual salary of RS 5000 & received increment of Rs 200 each year. In which year did his income become 70000 ?
5. Rakali earned Rs 5 in the first week . Each week the increment was Rs 1.75 ; Which week her income is Rs 20.75 ?
HW 2 SUB TOPIC : Sum of n terms of an AP – statement problems
1. How many terms of the AP 9 , 17 , 25 , … must be taken to form a sum of 636 ?
2. The first term of an AP is 5 , the last term is 45 & sum is 400 . Find number of terms & common difference
3. Find the sum of first 51 terms of an AP , whose second & third term are 14 & 18 ?
4. Find the sum of the first 40 positive integers divisible by 6
5. Find the sum of first 15 multiples of 8
6. Show that a1 , a2 , a3 …an form an AP , where a is defined as below
SUBMISSION DATE: 10.08.2017
PAIR OF LINEAR EQNS IN TWO VARIABLES CLASS : 10 HOMEWORK FOR THE WEEK 11.07 .17 TO 18.07.17
SUBJECT : MATHEMATICS TOPIC : PAIR OF LINEAR EQNS IN TWO VARIABLES
SUBMISSION DATE : 19 .07.17
HW 1 SUB TOPIC : ALGEBRAIC METHOD OF
SOLVING THE PAIR OF EQUATION
1 1. Solve the following pair of
equations by substitution method
(a)
X + y = 14 , x –
y = 4
(b)
5 – t = 3 , 5/3
+ t/2 = 6
(c)
0.2 x + 0.3 y = 1.3 , 0.4
x + 0.5 y = 2.3
(d)
3/2 x – 5/3 y = - 2 ,
x/3 + y/2 = 13/6
2 2. The coach of a cricket team
buys 7 bats & 6 balls for Rs 3800 . Later she buys 3 bats & 5 balls for
Rs 1750 . Find the cost of a bat & a ball
3. 3. Five years hence the age of
Jacob will be three times that of his son. Five years ago Jacob’s age was seven
time the age of his son. What are their present ages ?
HW 2 SUB TOPIC : ALGEBRAIC METHOD OF SOLVING THE
PAIR OF EQUATION
1. 1. Solve the following pair of
equations by elimination method
(a)
3x – 5 y = 4 , 9x =
2y + 7
(b)
x/2 + 2y/3 = - 1 , x – y/3
= 3
2. 2. Five years ago Nuri was thrice
as old as Sonu . Ten years later Nuri will be twice as old as Sonu. Find their
present ages
HW 3 SUB TOPIC : ALGEBRAIC METHOD OF SOLVING THE
PAIR OF EQUATION
1. 1. Find whether the pair of
equations have unique solution , no solution or infinetly many solutions ? In
case of unique solution , find it b cross multiplication method
(a)
3x – 5y = 20 , 6x – 10y
= 40
(b)
X – 3y – 7 =0 ,
3x – 3y – 15 = 0
2. 2. A fraction becomes 1/3 when 1
is subtracted from the numerator & it becomes ¼ when 8 is added to the denominator . Find the
fraction
HW 4 SUB TOPIC : ALGEBRAIC METHOD OF SOLVING THE
PAIR OF EQUATION
1. 1. Solve the following pair of
equations by reducing them to linear form
(a)
4/x + 3y = 14 , 3/x
– 4y = 23
(b)
6x + 3y = 6xy , 2x + 4y = 5xy
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SUBMISSION DATE : 11 .07.17
HW 1 SUB TOPIC : ALGEBRAIC &
GRAPHICAL REPRESENTATION OF STATEMENTS
1. The coach of a cricket team buys 3 bats and
6 balls for Rs 3900 . Later she buys another bat & 3 more balls of the same
kind for Rs 1300. Represent this situation algebraically & geometrically
2. The cost of 2 Kg apples & 1 Kg grapes
on a day was found to be Rs 160. After a month the cost of 4 Kg of apples &
2 Kg of grapes is Rs 300 . Represent this situation algebraically &
geometrically
HW 2 SUB TOPIC : GRAPHICAL METHOD OF SOLUTION OF A
PAIR OF LINEAR EQNS
1.
5 Pencils & 7 pens together
cost Rs 50,whereas 7 pencils & 5 pens cost Rs 46 .Find the cost of one pen
& a pencil
2.
Compare the ratios a1/a2 , b1/b2
& c1/c2 & find whether the following pairs of linear eqns
intersect at a point, are parallel or coincident
(i)
5x – 4y +8 = 0 ,
7x + 6y – 9 = 0
(ii)
9x + 3y +12 = 0 , 18
x + 6y +24 = 0
(iii)
6x – 3 y +10 = 0 , 2x
– y + 9 = 0
3.
On comparing the ratios of
a1/a2 , b1/b2 & c1/c2 find out whether the following pairs of linear eqns
are consistent or inconsistent
(i)
3x + 2y = 5 , 2x –
3 y = 7
(ii)
2x – 3 y = 8 , 4x –
6 y = 9
(iii)
3/2 x + 5/3 y = 7 , 9x –
10 y = 14
(iv)
5x – 3 y = 11 , 10x
+ 6y = -22
(v)
4/3 x + 2y = 8 , 2x + 3y = 12
4.
Find whether the following
pairs are consistent or inconsistent ? If consistent obtain the solution
graphically
(i)
x+y = 5
, 2x + 2y = 10
(ii)
X- y = 8 , 3x
– 3 y =16
(iii)
2x+y – 6 = 0 , 4x –
2 y – 4 = 0
(iv)
2x – 2y = 2 = 0 , 4x –
4 y – 5 = 0
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